2(x-4)+3(x+2)=4(x+5)

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Solution for 2(x-4)+3(x+2)=4(x+5) equation: 



2(x-4)+3(x+2)=4(x+5)

We move all terms to the left:

2(x-4)+3(x+2)-(4(x+5))=0

We multiply parentheses

2x+3x-(4(x+5))-8+6=0



We calculate terms in parentheses: -(4(x+5)), so:

4(x+5)

We multiply parentheses

4x+20

Back to the equation:

-(4x+20)



We add all the numbers together, and all the variables

5x-(4x+20)-2=0

We get rid of parentheses

5x-4x-20-2=0

We add all the numbers together, and all the variables

x-22=0

We move all terms containing x to the left, all other terms to the right

x=22

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