2(x-4)+3(x+6)=20

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Solution for 2(x-4)+3(x+6)=20 equation: 



2(x-4)+3(x+6)=20

We move all terms to the left:

2(x-4)+3(x+6)-(20)=0

We multiply parentheses

2x+3x-8+18-20=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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