2(x-4)+3(x-20)=3x-10

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Solution for 2(x-4)+3(x-20)=3x-10 equation: 



2(x-4)+3(x-20)=3x-10

We move all terms to the left:

2(x-4)+3(x-20)-(3x-10)=0

We multiply parentheses

2x+3x-(3x-10)-8-60=0

We get rid of parentheses

2x+3x-3x+10-8-60=0

We add all the numbers together, and all the variables

2x-58=0

We move all terms containing x to the left, all other terms to the right

2x=58

x=58/2

x=29

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