2(x-4)+3=3(2x-5)+10-4x

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Solution for 2(x-4)+3=3(2x-5)+10-4x equation: 



2(x-4)+3=3(2x-5)+10-4x

We move all terms to the left:

2(x-4)+3-(3(2x-5)+10-4x)=0

We multiply parentheses

2x-(3(2x-5)+10-4x)-8+3=0



We calculate terms in parentheses: -(3(2x-5)+10-4x), so:

3(2x-5)+10-4x

determiningTheFunctionDomain
3(2x-5)-4x+10

We add all the numbers together, and all the variables

-4x+3(2x-5)+10

We multiply parentheses

-4x+6x-15+10

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

2x-(2x-5)-5=0

We get rid of parentheses

2x-2x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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