2(x-4)+3=6x+7

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Solution for 2(x-4)+3=6x+7 equation: 



2(x-4)+3=6x+7

We move all terms to the left:

2(x-4)+3-(6x+7)=0

We multiply parentheses

2x-(6x+7)-8+3=0

We get rid of parentheses

2x-6x-7-8+3=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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