2(x-4)+3x=-3(x+2)

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Solution for 2(x-4)+3x=-3(x+2) equation: 



2(x-4)+3x=-3(x+2)

We move all terms to the left:

2(x-4)+3x-(-3(x+2))=0

We add all the numbers together, and all the variables

3x+2(x-4)-(-3(x+2))=0

We multiply parentheses

3x+2x-(-3(x+2))-8=0



We calculate terms in parentheses: -(-3(x+2)), so:

-3(x+2)

We multiply parentheses

-3x-6

Back to the equation:

-(-3x-6)



We add all the numbers together, and all the variables

5x-(-3x-6)-8=0

We get rid of parentheses

5x+3x+6-8=0

We add all the numbers together, and all the variables

8x-2=0

We move all terms containing x to the left, all other terms to the right

8x=2

x=2/8

x=1/4

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