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2(x-4)+4=4x-2(1+x)
We move all terms to the left:
2(x-4)+4-(4x-2(1+x))=0
We add all the numbers together, and all the variables
2(x-4)-(4x-2(x+1))+4=0
We multiply parentheses
2x-(4x-2(x+1))-8+4=0
We calculate terms in parentheses: -(4x-2(x+1)), so:We add all the numbers together, and all the variables
4x-2(x+1)
We multiply parentheses
4x-2x-2
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
2x-(2x-2)-4=0
We get rid of parentheses
2x-2x+2-4=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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