2(x-4)+4x=4(x+8)

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Solution for 2(x-4)+4x=4(x+8) equation: 



2(x-4)+4x=4(x+8)

We move all terms to the left:

2(x-4)+4x-(4(x+8))=0

We add all the numbers together, and all the variables

4x+2(x-4)-(4(x+8))=0

We multiply parentheses

4x+2x-(4(x+8))-8=0



We calculate terms in parentheses: -(4(x+8)), so:

4(x+8)

We multiply parentheses

4x+32

Back to the equation:

-(4x+32)



We add all the numbers together, and all the variables

6x-(4x+32)-8=0

We get rid of parentheses

6x-4x-32-8=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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