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2(x-4)+4x=45-5(2x+1)
We move all terms to the left:
2(x-4)+4x-(45-5(2x+1))=0
We add all the numbers together, and all the variables
4x+2(x-4)-(45-5(2x+1))=0
We multiply parentheses
4x+2x-(45-5(2x+1))-8=0
We calculate terms in parentheses: -(45-5(2x+1)), so:We add all the numbers together, and all the variables
45-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+45
We multiply parentheses
-10x-5+45
We add all the numbers together, and all the variables
-10x+40
Back to the equation:
-(-10x+40)
6x-(-10x+40)-8=0
We get rid of parentheses
6x+10x-40-8=0
We add all the numbers together, and all the variables
16x-48=0
We move all terms containing x to the left, all other terms to the right
16x=48
x=48/16
x=3
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