2(x-4)+5x=41

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Solution for 2(x-4)+5x=41 equation: 



2(x-4)+5x=41

We move all terms to the left:

2(x-4)+5x-(41)=0

We add all the numbers together, and all the variables

5x+2(x-4)-41=0

We multiply parentheses

5x+2x-8-41=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7

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