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2(x-4)+6x=4(2x+3)-11
We move all terms to the left:
2(x-4)+6x-(4(2x+3)-11)=0
We add all the numbers together, and all the variables
6x+2(x-4)-(4(2x+3)-11)=0
We multiply parentheses
6x+2x-(4(2x+3)-11)-8=0
We calculate terms in parentheses: -(4(2x+3)-11), so:We add all the numbers together, and all the variables
4(2x+3)-11
We multiply parentheses
8x+12-11
We add all the numbers together, and all the variables
8x+1
Back to the equation:
-(8x+1)
8x-(8x+1)-8=0
We get rid of parentheses
8x-8x-1-8=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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