2(x-4)+x=3(x-5)+7

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Solution for 2(x-4)+x=3(x-5)+7 equation: 



2(x-4)+x=3(x-5)+7

We move all terms to the left:

2(x-4)+x-(3(x-5)+7)=0

We add all the numbers together, and all the variables

x+2(x-4)-(3(x-5)+7)=0

We multiply parentheses

x+2x-(3(x-5)+7)-8=0



We calculate terms in parentheses: -(3(x-5)+7), so:

3(x-5)+7

We multiply parentheses

3x-15+7

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We add all the numbers together, and all the variables

3x-(3x-8)-8=0

We get rid of parentheses

3x-3x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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