2(x-4)+x=3(x-6)+10

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Solution for 2(x-4)+x=3(x-6)+10 equation: 


Simplifying
2(x + -4) + x = 3(x + -6) + 10

Reorder the terms:
2(-4 + x) + x = 3(x + -6) + 10
(-4 * 2 + x * 2) + x = 3(x + -6) + 10
(-8 + 2x) + x = 3(x + -6) + 10

Combine like terms: 2x + x = 3x
-8 + 3x = 3(x + -6) + 10

Reorder the terms:
-8 + 3x = 3(-6 + x) + 10
-8 + 3x = (-6 * 3 + x * 3) + 10
-8 + 3x = (-18 + 3x) + 10

Reorder the terms:
-8 + 3x = -18 + 10 + 3x

Combine like terms: -18 + 10 = -8
-8 + 3x = -8 + 3x

Add '8' to each side of the equation.
-8 + 8 + 3x = -8 + 8 + 3x

Combine like terms: -8 + 8 = 0
0 + 3x = -8 + 8 + 3x
3x = -8 + 8 + 3x

Combine like terms: -8 + 8 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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