2(x-4)+x=3(x-7)+13

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Solution for 2(x-4)+x=3(x-7)+13 equation: 


Simplifying
2(x + -4) + x = 3(x + -7) + 13

Reorder the terms:
2(-4 + x) + x = 3(x + -7) + 13
(-4 * 2 + x * 2) + x = 3(x + -7) + 13
(-8 + 2x) + x = 3(x + -7) + 13

Combine like terms: 2x + x = 3x
-8 + 3x = 3(x + -7) + 13

Reorder the terms:
-8 + 3x = 3(-7 + x) + 13
-8 + 3x = (-7 * 3 + x * 3) + 13
-8 + 3x = (-21 + 3x) + 13

Reorder the terms:
-8 + 3x = -21 + 13 + 3x

Combine like terms: -21 + 13 = -8
-8 + 3x = -8 + 3x

Add '8' to each side of the equation.
-8 + 8 + 3x = -8 + 8 + 3x

Combine like terms: -8 + 8 = 0
0 + 3x = -8 + 8 + 3x
3x = -8 + 8 + 3x

Combine like terms: -8 + 8 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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