2(x-4)+x=7+3(x+1)

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Solution for 2(x-4)+x=7+3(x+1) equation: 



2(x-4)+x=7+3(x+1)

We move all terms to the left:

2(x-4)+x-(7+3(x+1))=0

We add all the numbers together, and all the variables

x+2(x-4)-(7+3(x+1))=0

We multiply parentheses

x+2x-(7+3(x+1))-8=0



We calculate terms in parentheses: -(7+3(x+1)), so:

7+3(x+1)

determiningTheFunctionDomain
3(x+1)+7

We multiply parentheses

3x+3+7

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We add all the numbers together, and all the variables

3x-(3x+10)-8=0

We get rid of parentheses

3x-3x-10-8=0

We add all the numbers together, and all the variables

-18!=0

There is no solution for this equation

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