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2(x-4)-(4x+3)=3(4x+5)
We move all terms to the left:
2(x-4)-(4x+3)-(3(4x+5))=0
We multiply parentheses
2x-(4x+3)-(3(4x+5))-8=0
We get rid of parentheses
2x-4x-(3(4x+5))-3-8=0
We calculate terms in parentheses: -(3(4x+5)), so:We add all the numbers together, and all the variables
3(4x+5)
We multiply parentheses
12x+15
Back to the equation:
-(12x+15)
-2x-(12x+15)-11=0
We get rid of parentheses
-2x-12x-15-11=0
We add all the numbers together, and all the variables
-14x-26=0
We move all terms containing x to the left, all other terms to the right
-14x=26
x=26/-14
x=-1+6/7
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