2(x-4)-(x+2)=x-5(x-2)

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Solution for 2(x-4)-(x+2)=x-5(x-2) equation: 



2(x-4)-(x+2)=x-5(x-2)

We move all terms to the left:

2(x-4)-(x+2)-(x-5(x-2))=0

We multiply parentheses

2x-(x+2)-(x-5(x-2))-8=0

We get rid of parentheses

2x-x-(x-5(x-2))-2-8=0



We calculate terms in parentheses: -(x-5(x-2)), so:

x-5(x-2)

We multiply parentheses

x-5x+10

We add all the numbers together, and all the variables

-4x+10

Back to the equation:

-(-4x+10)



We add all the numbers together, and all the variables

x-(-4x+10)-10=0

We get rid of parentheses

x+4x-10-10=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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