2(x-4)-(x-2)=(x+2)+12

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Solution for 2(x-4)-(x-2)=(x+2)+12 equation: 



2(x-4)-(x-2)=(x+2)+12

We move all terms to the left:

2(x-4)-(x-2)-((x+2)+12)=0

We multiply parentheses

2x-(x-2)-((x+2)+12)-8=0

We get rid of parentheses

2x-x-((x+2)+12)+2-8=0



We calculate terms in parentheses: -((x+2)+12), so:

(x+2)+12

We get rid of parentheses

x+2+12

We add all the numbers together, and all the variables

x+14

Back to the equation:

-(x+14)



We add all the numbers together, and all the variables

x-(x+14)-6=0

We get rid of parentheses

x-x-14-6=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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