2(x-4)-2=-3(-6x+4)-8x

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Solution for 2(x-4)-2=-3(-6x+4)-8x equation: 



2(x-4)-2=-3(-6x+4)-8x

We move all terms to the left:

2(x-4)-2-(-3(-6x+4)-8x)=0

We multiply parentheses

2x-(-3(-6x+4)-8x)-8-2=0



We calculate terms in parentheses: -(-3(-6x+4)-8x), so:

-3(-6x+4)-8x

We add all the numbers together, and all the variables

-8x-3(-6x+4)

We multiply parentheses

-8x+18x-12

We add all the numbers together, and all the variables

10x-12

Back to the equation:

-(10x-12)



We add all the numbers together, and all the variables

2x-(10x-12)-10=0

We get rid of parentheses

2x-10x+12-10=0

We add all the numbers together, and all the variables

-8x+2=0

We move all terms containing x to the left, all other terms to the right

-8x=-2

x=-2/-8

x=1/4

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