2(x-4)-2=3(x+1)+5

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Solution for 2(x-4)-2=3(x+1)+5 equation: 



2(x-4)-2=3(x+1)+5

We move all terms to the left:

2(x-4)-2-(3(x+1)+5)=0

We multiply parentheses

2x-(3(x+1)+5)-8-2=0



We calculate terms in parentheses: -(3(x+1)+5), so:

3(x+1)+5

We multiply parentheses

3x+3+5

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

2x-(3x+8)-10=0

We get rid of parentheses

2x-3x-8-10=0

We add all the numbers together, and all the variables

-1x-18=0

We move all terms containing x to the left, all other terms to the right

-x=18

x=18/-1

x=-18

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