2(x-4)-3(x-5)=-3(x-2)-4

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Solution for 2(x-4)-3(x-5)=-3(x-2)-4 equation: 



2(x-4)-3(x-5)=-3(x-2)-4

We move all terms to the left:

2(x-4)-3(x-5)-(-3(x-2)-4)=0

We multiply parentheses

2x-3x-(-3(x-2)-4)-8+15=0



We calculate terms in parentheses: -(-3(x-2)-4), so:

-3(x-2)-4

We multiply parentheses

-3x+6-4

We add all the numbers together, and all the variables

-3x+2

Back to the equation:

-(-3x+2)



We add all the numbers together, and all the variables

-1x-(-3x+2)+7=0

We get rid of parentheses

-1x+3x-2+7=0

We add all the numbers together, and all the variables

2x+5=0

We move all terms containing x to the left, all other terms to the right

2x=-5

x=-5/2

x=-2+1/2

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