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2(x-4)-3(x-5)=-3(x-2)-4
We move all terms to the left:
2(x-4)-3(x-5)-(-3(x-2)-4)=0
We multiply parentheses
2x-3x-(-3(x-2)-4)-8+15=0
We calculate terms in parentheses: -(-3(x-2)-4), so:We add all the numbers together, and all the variables
-3(x-2)-4
We multiply parentheses
-3x+6-4
We add all the numbers together, and all the variables
-3x+2
Back to the equation:
-(-3x+2)
-1x-(-3x+2)+7=0
We get rid of parentheses
-1x+3x-2+7=0
We add all the numbers together, and all the variables
2x+5=0
We move all terms containing x to the left, all other terms to the right
2x=-5
x=-5/2
x=-2+1/2
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