2(x-4)-3(x1+x)=-6x

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Solution for 2(x-4)-3(x1+x)=-6x equation: 



2(x-4)-3(x1+x)=-6x

We move all terms to the left:

2(x-4)-3(x1+x)-(-6x)=0

We add all the numbers together, and all the variables

2(x-4)-3(+2x)-(-6x)=0

We multiply parentheses

2x-6x-(-6x)-8=0

We get rid of parentheses

2x-6x+6x-8=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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