2(x-4)-4(x-2)=x+7-(x-5)

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Solution for 2(x-4)-4(x-2)=x+7-(x-5) equation: 



2(x-4)-4(x-2)=x+7-(x-5)

We move all terms to the left:

2(x-4)-4(x-2)-(x+7-(x-5))=0

We multiply parentheses

2x-4x-(x+7-(x-5))-8+8=0



We calculate terms in parentheses: -(x+7-(x-5)), so:

x+7-(x-5)

determiningTheFunctionDomain
x-(x-5)+7

We get rid of parentheses

x-x+5+7

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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