2(x-4)-4x=3(x-3)+6

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Solution for 2(x-4)-4x=3(x-3)+6 equation: 



2(x-4)-4x=3(x-3)+6

We move all terms to the left:

2(x-4)-4x-(3(x-3)+6)=0

We add all the numbers together, and all the variables

-4x+2(x-4)-(3(x-3)+6)=0

We multiply parentheses

-4x+2x-(3(x-3)+6)-8=0



We calculate terms in parentheses: -(3(x-3)+6), so:

3(x-3)+6

We multiply parentheses

3x-9+6

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

-2x-(3x-3)-8=0

We get rid of parentheses

-2x-3x+3-8=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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