2(x-4)-6=-2(-8x+1)-4x

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Solution for 2(x-4)-6=-2(-8x+1)-4x equation: 



2(x-4)-6=-2(-8x+1)-4x

We move all terms to the left:

2(x-4)-6-(-2(-8x+1)-4x)=0

We multiply parentheses

2x-(-2(-8x+1)-4x)-8-6=0



We calculate terms in parentheses: -(-2(-8x+1)-4x), so:

-2(-8x+1)-4x

We add all the numbers together, and all the variables

-4x-2(-8x+1)

We multiply parentheses

-4x+16x-2

We add all the numbers together, and all the variables

12x-2

Back to the equation:

-(12x-2)



We add all the numbers together, and all the variables

2x-(12x-2)-14=0

We get rid of parentheses

2x-12x+2-14=0

We add all the numbers together, and all the variables

-10x-12=0

We move all terms containing x to the left, all other terms to the right

-10x=12

x=12/-10

x=-1+1/5

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