2(x-4)/3=4(2x-1)/15

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Solution for 2(x-4)/3=4(2x-1)/15 equation:



2(x-4)/3=4(2x-1)/15
We move all terms to the left:
2(x-4)/3-(4(2x-1)/15)=0
We calculate fractions
2x/()+(-(4(2x-1)*3)/()=0
We calculate terms in parentheses: +(-(4(2x-1)*3)/(), so:
-(4(2x-1)*3)/(
We multiply all the terms by the denominator
-(4(2x-1)*3)
We calculate terms in parentheses: -(4(2x-1)*3), so:
4(2x-1)*3
We multiply parentheses
24x-12
Back to the equation:
-(24x-12)
We get rid of parentheses
-24x+12
Back to the equation:
+(-24x+12)
We get rid of parentheses
2x/()-24x+12=0
We multiply all the terms by the denominator
2x-24x*()+12*()=0
We add all the numbers together, and all the variables
2x-24x*()=0

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