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2(x-4)=-4(2x-1)+10x
We move all terms to the left:
2(x-4)-(-4(2x-1)+10x)=0
We multiply parentheses
2x-(-4(2x-1)+10x)-8=0
We calculate terms in parentheses: -(-4(2x-1)+10x), so:We get rid of parentheses
-4(2x-1)+10x
We add all the numbers together, and all the variables
10x-4(2x-1)
We multiply parentheses
10x-8x+4
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
2x-2x-4-8=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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