2(x-4)=10-(2-12x)

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Solution for 2(x-4)=10-(2-12x) equation: 



2(x-4)=10-(2-12x)

We move all terms to the left:

2(x-4)-(10-(2-12x))=0

We add all the numbers together, and all the variables

2(x-4)-(10-(-12x+2))=0

We multiply parentheses

2x-(10-(-12x+2))-8=0



We calculate terms in parentheses: -(10-(-12x+2)), so:

10-(-12x+2)

determiningTheFunctionDomain
-(-12x+2)+10

We get rid of parentheses

12x-2+10

We add all the numbers together, and all the variables

12x+8

Back to the equation:

-(12x+8)



We get rid of parentheses

2x-12x-8-8=0

We add all the numbers together, and all the variables

-10x-16=0

We move all terms containing x to the left, all other terms to the right

-10x=16

x=16/-10

x=-1+3/5

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