2(x-4)=10-(x-3)

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Solution for 2(x-4)=10-(x-3) equation: 



2(x-4)=10-(x-3)

We move all terms to the left:

2(x-4)-(10-(x-3))=0

We multiply parentheses

2x-(10-(x-3))-8=0



We calculate terms in parentheses: -(10-(x-3)), so:

10-(x-3)

determiningTheFunctionDomain
-(x-3)+10

We get rid of parentheses

-x+3+10

We add all the numbers together, and all the variables

-1x+13

Back to the equation:

-(-1x+13)



We get rid of parentheses

2x+1x-13-8=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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