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2(x-4)=10-6(2x+1)
We move all terms to the left:
2(x-4)-(10-6(2x+1))=0
We multiply parentheses
2x-(10-6(2x+1))-8=0
We calculate terms in parentheses: -(10-6(2x+1)), so:We get rid of parentheses
10-6(2x+1)
determiningTheFunctionDomain -6(2x+1)+10
We multiply parentheses
-12x-6+10
We add all the numbers together, and all the variables
-12x+4
Back to the equation:
-(-12x+4)
2x+12x-4-8=0
We add all the numbers together, and all the variables
14x-12=0
We move all terms containing x to the left, all other terms to the right
14x=12
x=12/14
x=6/7
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