2(x-4)=13-7(2x+1)

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Solution for 2(x-4)=13-7(2x+1) equation: 



2(x-4)=13-7(2x+1)

We move all terms to the left:

2(x-4)-(13-7(2x+1))=0

We multiply parentheses

2x-(13-7(2x+1))-8=0



We calculate terms in parentheses: -(13-7(2x+1)), so:

13-7(2x+1)

determiningTheFunctionDomain
-7(2x+1)+13

We multiply parentheses

-14x-7+13

We add all the numbers together, and all the variables

-14x+6

Back to the equation:

-(-14x+6)



We get rid of parentheses

2x+14x-6-8=0

We add all the numbers together, and all the variables

16x-14=0

We move all terms containing x to the left, all other terms to the right

16x=14

x=14/16

x=7/8

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