2(x-4)=2+3(x+6)

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Solution for 2(x-4)=2+3(x+6) equation: 



2(x-4)=2+3(x+6)

We move all terms to the left:

2(x-4)-(2+3(x+6))=0

We multiply parentheses

2x-(2+3(x+6))-8=0



We calculate terms in parentheses: -(2+3(x+6)), so:

2+3(x+6)

determiningTheFunctionDomain
3(x+6)+2

We multiply parentheses

3x+18+2

We add all the numbers together, and all the variables

3x+20

Back to the equation:

-(3x+20)



We get rid of parentheses

2x-3x-20-8=0

We add all the numbers together, and all the variables

-1x-28=0

We move all terms containing x to the left, all other terms to the right

-x=28

x=28/-1

x=-28

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