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2(x-4)=3(2x+2)
We move all terms to the left:
2(x-4)-(3(2x+2))=0
We multiply parentheses
2x-(3(2x+2))-8=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
2x-6x-6-8=0
We add all the numbers together, and all the variables
-4x-14=0
We move all terms containing x to the left, all other terms to the right
-4x=14
x=14/-4
x=-3+1/2
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