2(x-4)=3(2x-3)+33

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Solution for 2(x-4)=3(2x-3)+33 equation: 



2(x-4)=3(2x-3)+33

We move all terms to the left:

2(x-4)-(3(2x-3)+33)=0

We multiply parentheses

2x-(3(2x-3)+33)-8=0



We calculate terms in parentheses: -(3(2x-3)+33), so:

3(2x-3)+33

We multiply parentheses

6x-9+33

We add all the numbers together, and all the variables

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

2x-6x-24-8=0

We add all the numbers together, and all the variables

-4x-32=0

We move all terms containing x to the left, all other terms to the right

-4x=32

x=32/-4

x=-8

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