2(x-4)=3(x-2)-2

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Solution for 2(x-4)=3(x-2)-2 equation: 



2(x-4)=3(x-2)-2

We move all terms to the left:

2(x-4)-(3(x-2)-2)=0

We multiply parentheses

2x-(3(x-2)-2)-8=0



We calculate terms in parentheses: -(3(x-2)-2), so:

3(x-2)-2

We multiply parentheses

3x-6-2

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We get rid of parentheses

2x-3x+8-8=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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