2(x-4)=3x+11(2x+5)-7

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Solution for 2(x-4)=3x+11(2x+5)-7 equation: 



2(x-4)=3x+11(2x+5)-7

We move all terms to the left:

2(x-4)-(3x+11(2x+5)-7)=0

We multiply parentheses

2x-(3x+11(2x+5)-7)-8=0



We calculate terms in parentheses: -(3x+11(2x+5)-7), so:

3x+11(2x+5)-7

We multiply parentheses

3x+22x+55-7

We add all the numbers together, and all the variables

25x+48

Back to the equation:

-(25x+48)



We get rid of parentheses

2x-25x-48-8=0

We add all the numbers together, and all the variables

-23x-56=0

We move all terms containing x to the left, all other terms to the right

-23x=56

x=56/-23

x=-2+10/23

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