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2(x-4)=3x-(2x+4)
We move all terms to the left:
2(x-4)-(3x-(2x+4))=0
We multiply parentheses
2x-(3x-(2x+4))-8=0
We calculate terms in parentheses: -(3x-(2x+4)), so:We get rid of parentheses
3x-(2x+4)
We get rid of parentheses
3x-2x-4
We add all the numbers together, and all the variables
x-4
Back to the equation:
-(x-4)
2x-x+4-8=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4
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