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2(x-4)=4(2x+10)
We move all terms to the left:
2(x-4)-(4(2x+10))=0
We multiply parentheses
2x-(4(2x+10))-8=0
We calculate terms in parentheses: -(4(2x+10)), so:We get rid of parentheses
4(2x+10)
We multiply parentheses
8x+40
Back to the equation:
-(8x+40)
2x-8x-40-8=0
We add all the numbers together, and all the variables
-6x-48=0
We move all terms containing x to the left, all other terms to the right
-6x=48
x=48/-6
x=-8
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