2(x-4)=4(x2+1)

Solution for 2(x-4)=4(x2+1) equation:

2(x-4)=4(x2+1)

We move all terms to the left:

2(x-4)-(4(x2+1))=0

We add all the numbers together, and all the variables

-(4(+x^2+1))+2(x-4)=0

We multiply parentheses

-(4(+x^2+1))+2x-8=0


We calculate terms in parentheses: -(4(+x^2+1)), so:

4(+x^2+1)

We multiply parentheses

4x^2+4

Back to the equation:

-(4x^2+4)


We add all the numbers together, and all the variables

2x-(4x^2+4)-8=0

We get rid of parentheses

-4x^2+2x-4-8=0

We add all the numbers together, and all the variables

-4x^2+2x-12=0

a = -4; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·(-4)·(-12)
Δ = -188
Delta is less than zero, so there is no solution for the equation