2(x-4)=4x+3X+3x+12

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Solution for 2(x-4)=4x+3X+3x+12 equation:



2(x-4)=4x+3x+3x+12
We move all terms to the left:
2(x-4)-(4x+3x+3x+12)=0
We add all the numbers together, and all the variables
2(x-4)-(10x+12)=0
We multiply parentheses
2x-(10x+12)-8=0
We get rid of parentheses
2x-10x-12-8=0
We add all the numbers together, and all the variables
-8x-20=0
We move all terms containing x to the left, all other terms to the right
-8x=20
x=20/-8
x=-2+1/2

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