2(x-4)=4x+3X+3x+12

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Solution for 2(x-4)=4x+3X+3x+12 equation: 



2(x-4)=4x+3x+3x+12

We move all terms to the left:

2(x-4)-(4x+3x+3x+12)=0

We add all the numbers together, and all the variables

2(x-4)-(10x+12)=0

We multiply parentheses

2x-(10x+12)-8=0

We get rid of parentheses

2x-10x-12-8=0

We add all the numbers together, and all the variables

-8x-20=0

We move all terms containing x to the left, all other terms to the right

-8x=20

x=20/-8

x=-2+1/2

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