2(x-4)=4x-2(x+4)

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Solution for 2(x-4)=4x-2(x+4) equation: 



2(x-4)=4x-2(x+4)

We move all terms to the left:

2(x-4)-(4x-2(x+4))=0

We multiply parentheses

2x-(4x-2(x+4))-8=0



We calculate terms in parentheses: -(4x-2(x+4)), so:

4x-2(x+4)

We multiply parentheses

4x-2x-8

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

2x-2x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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