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2(x-4)=5(4-2x)
We move all terms to the left:
2(x-4)-(5(4-2x))=0
We add all the numbers together, and all the variables
2(x-4)-(5(-2x+4))=0
We multiply parentheses
2x-(5(-2x+4))-8=0
We calculate terms in parentheses: -(5(-2x+4)), so:We get rid of parentheses
5(-2x+4)
We multiply parentheses
-10x+20
Back to the equation:
-(-10x+20)
2x+10x-20-8=0
We add all the numbers together, and all the variables
12x-28=0
We move all terms containing x to the left, all other terms to the right
12x=28
x=28/12
x=2+1/3
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