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2(x-4)=5(4-2x)+4x.
We move all terms to the left:
2(x-4)-(5(4-2x)+4x.)=0
We add all the numbers together, and all the variables
2(x-4)-(5(-2x+4)+4x.)=0
We multiply parentheses
2x-(5(-2x+4)+4x.)-8=0
We calculate terms in parentheses: -(5(-2x+4)+4x.), so:We get rid of parentheses
5(-2x+4)+4x.
We multiply parentheses
-10x+4x.+20
Back to the equation:
-(-10x+4x.+20)
2x+10x-4x.-20-8=0
We add all the numbers together, and all the variables
12x-4x.-28=0
We move all terms containing x to the left, all other terms to the right
12x-4x.=28
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