2(x-4)=6(8-x)

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Solution for 2(x-4)=6(8-x) equation:



2(x-4)=6(8-x)
We move all terms to the left:
2(x-4)-(6(8-x))=0
We add all the numbers together, and all the variables
2(x-4)-(6(-1x+8))=0
We multiply parentheses
2x-(6(-1x+8))-8=0
We calculate terms in parentheses: -(6(-1x+8)), so:
6(-1x+8)
We multiply parentheses
-6x+48
Back to the equation:
-(-6x+48)
We get rid of parentheses
2x+6x-48-8=0
We add all the numbers together, and all the variables
8x-56=0
We move all terms containing x to the left, all other terms to the right
8x=56
x=56/8
x=7

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