2(x-4)=6x+2-2(-4x-3)

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Solution for 2(x-4)=6x+2-2(-4x-3) equation: 



2(x-4)=6x+2-2(-4x-3)

We move all terms to the left:

2(x-4)-(6x+2-2(-4x-3))=0

We multiply parentheses

2x-(6x+2-2(-4x-3))-8=0



We calculate terms in parentheses: -(6x+2-2(-4x-3)), so:

6x+2-2(-4x-3)

determiningTheFunctionDomain
6x-2(-4x-3)+2

We multiply parentheses

6x+8x+6+2

We add all the numbers together, and all the variables

14x+8

Back to the equation:

-(14x+8)



We get rid of parentheses

2x-14x-8-8=0

We add all the numbers together, and all the variables

-12x-16=0

We move all terms containing x to the left, all other terms to the right

-12x=16

x=16/-12

x=-1+1/3

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