2(x-4)=6x+3-3(-4x-1)

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Solution for 2(x-4)=6x+3-3(-4x-1) equation: 



2(x-4)=6x+3-3(-4x-1)

We move all terms to the left:

2(x-4)-(6x+3-3(-4x-1))=0

We multiply parentheses

2x-(6x+3-3(-4x-1))-8=0



We calculate terms in parentheses: -(6x+3-3(-4x-1)), so:

6x+3-3(-4x-1)

determiningTheFunctionDomain
6x-3(-4x-1)+3

We multiply parentheses

6x+12x+3+3

We add all the numbers together, and all the variables

18x+6

Back to the equation:

-(18x+6)



We get rid of parentheses

2x-18x-6-8=0

We add all the numbers together, and all the variables

-16x-14=0

We move all terms containing x to the left, all other terms to the right

-16x=14

x=14/-16

x=-7/8

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