2(x-4)=7-5(x-3)-3x

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Solution for 2(x-4)=7-5(x-3)-3x equation: 



2(x-4)=7-5(x-3)-3x

We move all terms to the left:

2(x-4)-(7-5(x-3)-3x)=0

We multiply parentheses

2x-(7-5(x-3)-3x)-8=0



We calculate terms in parentheses: -(7-5(x-3)-3x), so:

7-5(x-3)-3x

determiningTheFunctionDomain
-5(x-3)-3x+7

We add all the numbers together, and all the variables

-3x-5(x-3)+7

We multiply parentheses

-3x-5x+15+7

We add all the numbers together, and all the variables

-8x+22

Back to the equation:

-(-8x+22)



We get rid of parentheses

2x+8x-22-8=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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