2(x-4)=8(4+2x)

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Solution for 2(x-4)=8(4+2x) equation: 



2(x-4)=8(4+2x)

We move all terms to the left:

2(x-4)-(8(4+2x))=0

We add all the numbers together, and all the variables

2(x-4)-(8(2x+4))=0

We multiply parentheses

2x-(8(2x+4))-8=0



We calculate terms in parentheses: -(8(2x+4)), so:

8(2x+4)

We multiply parentheses

16x+32

Back to the equation:

-(16x+32)



We get rid of parentheses

2x-16x-32-8=0

We add all the numbers together, and all the variables

-14x-40=0

We move all terms containing x to the left, all other terms to the right

-14x=40

x=40/-14

x=-2+6/7

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