2(x-4i)(x+4i)=0

Solution for 2(x-4i)(x+4i)=0 equation:

Simplifying
2(x + -4i)(x + 4i) = 0

Reorder the terms:
2(-4i + x)(x + 4i) = 0

Reorder the terms:
2(-4i + x)(4i + x) = 0

Multiply (-4i + x) * (4i + x)
2(-4i * (4i + x) + x(4i + x)) = 0
2((4i * -4i + x * -4i) + x(4i + x)) = 0

Reorder the terms:
2((-4ix + -16i2) + x(4i + x)) = 0
2((-4ix + -16i2) + x(4i + x)) = 0
2(-4ix + -16i2 + (4i * x + x * x)) = 0
2(-4ix + -16i2 + (4ix + x2)) = 0

Reorder the terms:
2(-4ix + 4ix + -16i2 + x2) = 0

Combine like terms: -4ix + 4ix = 0
2(0 + -16i2 + x2) = 0
2(-16i2 + x2) = 0
(-16i2 * 2 + x2 * 2) = 0
(-32i2 + 2x2) = 0

Solving
-32i2 + 2x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-32i2 + 2x2 + -2x2 = 0 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-32i2 + 0 = 0 + -2x2
-32i2 = 0 + -2x2
Remove the zero:
-32i2 = -2x2

Divide each side by '-32'.
i2 = 0.0625x2

Simplifying
i2 = 0.0625x2

Take the square root of each side:
i = {-0.25x, 0.25x}