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2(x-5)(7x+4)=0
We multiply parentheses ..
2(+7x^2+4x-35x-20)=0
We multiply parentheses
14x^2+8x-70x-40=0
We add all the numbers together, and all the variables
14x^2-62x-40=0
a = 14; b = -62; c = -40;
Δ = b2-4ac
Δ = -622-4·14·(-40)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-78}{2*14}=\frac{-16}{28} =-4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+78}{2*14}=\frac{140}{28} =5 $
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